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Leetcode Problem 767. Reorganize String

767. Reorganize String

Leetcode Solutions

Counting and Odd/Even Index Placement

  1. Count the frequency of each character in the string s and store it in a hashmap or array.
  2. Find the character with the highest frequency and check if its count is more than half the length of the string rounded up. If so, return an empty string as it is impossible to rearrange.
  3. Initialize an array ans with the same length as s to store the rearranged characters.
  4. Start placing the most frequent character at even indices in ans until its count is depleted.
  5. Iterate through the remaining characters and place them at the next available even index, then move to odd indices once even indices are filled.
  6. Return the rearranged string by joining the elements in ans.
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Counting and Priority Queue

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