dfs(i, prev) that returns the minimum number of operations needed starting from index i with the previous group number prev.i is equal to the length of nums, return 0 as we have processed all elements.(i, prev) is already computed, return it from the memoization table.nums[i] is equal to prev, recursively call dfs(i+1, prev) as no operation is needed.nums[i] is less than prev, recursively call dfs(i+1, prev) and add 1 to the result as we need to perform an operation.nums[i] is greater than prev, we have two choices: leave it as is or change it to prev. Compute the minimum of dfs(i+1, nums[i]) and dfs(i+1, prev) + 1.dfs(0, 1) to get the final result.