Leetcode Problem 956. Tallest Billboard

956. Tallest Billboard

Leetcode Solutions

Dynamic Programming Approach

  1. Initialize a hashmap dp with a single entry {0: 0}.
  2. Iterate over each rod r in rods.
  3. Create a copy of dp called new_dp to store the updated states.
  4. For each (diff, taller) pair in dp, update new_dp with three possible states:
    • Skip the rod: already considered by copying dp to new_dp.
    • Add r to the taller stand: new_dp[diff + r] = max(new_dp.get(diff + r, 0), taller + r).
    • Add r to the shorter stand: new_diff = abs(diff - r) and new_taller = max(taller, diff + r); then new_dp[new_diff] = max(new_dp.get(new_diff, 0), new_taller).
  5. Assign new_dp back to dp.
  6. After iterating through all rods, return dp[0] as the maximum height of the billboard with equal height stands.
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Meet in the Middle Approach

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