Leetcode Problem 467. Unique Substrings in Wraparound String

467. Unique Substrings in Wraparound String

Leetcode Solutions

Dynamic Programming Approach to Count Unique Substrings in Wraparound String

  1. Initialize an array count of size 26 to store the length of the longest contiguous substring ending with each alphabet character.
  2. Initialize maxLengthCur to 0, which will store the length of the current contiguous substring.
  3. Iterate through each character c in the input string s. a. If c is the next character in the wraparound string after the previous character, increment maxLengthCur. b. Otherwise, reset maxLengthCur to 1. c. Calculate the index i for c in the alphabet (0 for 'a', 1 for 'b', ..., 25 for 'z'). d. Update count[i] to the maximum of its current value and maxLengthCur.
  4. After the iteration, sum up all values in count to get the total number of unique substrings.
  5. Return the sum as the final answer.
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Brute Force Approach to Count Unique Substrings in Wraparound String

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