nums.count to 0 to store the number of valid triangles.i and j, where i goes from 0 to len(nums) - 2 and j goes from i + 1 to len(nums) - 1.(i, j), initialize k to j + 1.k < len(nums) and nums[i] + nums[j] > nums[k], increment k.k - j - 1 to count.count.