Leetcode Problem 1024. Video Stitching

1024. Video Stitching

Leetcode Solutions

Greedy Approach with Sorting

  1. Sort the clips array based on the start time of each clip.
  2. Initialize curEnd to 0, farCanReach to 0, and total to 0.
  3. Iterate through the clips in a while loop until curEnd is less than time.
  4. Increment total to count the number of clips used.
  5. In a nested while loop, iterate through the clips as long as the current clip's start time is less than or equal to curEnd.
  6. Update farCanReach to the maximum of its current value and the end time of the current clip.
  7. If after considering all valid clips, farCanReach is equal to curEnd, return -1.
  8. Update curEnd to farCanReach.
  9. Once curEnd is greater than or equal to time, return total.
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Dynamic Programming Approach

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