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Leetcode Problem 280. Wiggle Sort
280. Wiggle Sort
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Leetcode Solutions
Greedy In-Place Swap Approach
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Algorithm Steps
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Complexity Analysis
Iterate over the array from the first element to the second-to-last element.
For every index
i
, check if it's even or odd.
If
i
is even and
nums[i]
is greater than
nums[i + 1]
, swap them.
If
i
is odd and
nums[i]
is less than
nums[i + 1]
, swap them.
Continue this process until the end of the array.
Sorting and Swapping Approach
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