bugfree Icon
interview-course
interview-course
interview-course
interview-course
interview-course
interview-course
interview-course
interview-course

Leetcode Problem 6. Zigzag Conversion

6. Zigzag Conversion

Leetcode Solutions

String Traversal without Extra Space

  1. Calculate the number of characters in a full zigzag cycle (charsInSection).
  2. Iterate over each row, starting from the top row to numRows.
  3. For each row, calculate the initial index (index) of the first character in that row.
  4. Within each row, iterate over the characters by calculating the appropriate jumps.
  5. If the row is not the first or last, calculate the index of the second character within the same section.
  6. Append characters found at these indices to the output string.
  7. Continue this process until the end of the string is reached.
  8. Return the output string.
UML Thumbnail

Simulate Zig-Zag Movement

Ask Question

Programming Language
image/screenshot of info(optional)
Full Screen
Loading...

Suggested Answer

Answer
Full Screen
Copy Answer Code
Loading...