NumArray(int[] nums) Initializes the object with the integer array nums.
int sumRange(int left, int right) Returns the sum of the elements of nums between indices left and right inclusive (i.e. nums[left] + nums[left + 1] + ... + nums[right]).

Example 1:

Input
["NumArray", "sumRange", "sumRange", "sumRange"]
[[[-2, 0, 3, -5, 2, -1]], [0, 2], [2, 5], [0, 5]]
Output
[null, 1, -1, -3]

Explanation
NumArray numArray = new NumArray([-2, 0, 3, -5, 2, -1]);
numArray.sumRange(0, 2); // return (-2) + 0 + 3 = 1
numArray.sumRange(2, 5); // return 3 + (-5) + 2 + (-1) = -1
numArray.sumRange(0, 5); // return (-2) + 0 + 3 + (-5) + 2 + (-1) = -3

Constraints:

1 <= nums.length <= 10⁴
-10⁵ <= nums[i] <= 10⁵
0 <= left <= right < nums.length
At most 10⁴ calls will be made to sumRange.

22:T485,Given an integer array `nums`, handle multiple queries of the following type: 1. Calculate the **sum** of the elements of `nums` between indices `left` and `right` **inclusive** where `left <= right`. Implement the `NumArray` class: * `NumArray(int[] nums)` Initializes the object with the integer array `nums`. * `int sumRange(int left, int right)` Returns the **sum** of the elements of `nums` between indices `left` and `right` **inclusive** (i.e. `nums[left] + nums[left + 1] + ... + nums[right]`). **Example 1:** **Input** ["NumArray", "sumRange", "sumRange", "sumRange"] [[[-2, 0, 3, -5, 2, -1]], [0, 2], [2, 5], [0, 5]] **Output** [null, 1, -1, -3] **Explanation** NumArray numArray = new NumArray([-

Range Sum Query - Immutable

Problem Description

Problem Description

Answer Panel