Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

Constraints:

1 <= n <= 10⁴

22:T455,# Intuition\n\n\n# Approach\n\n\n# Complexity\n- Time complexity:\n\n\n- Space complexity:\n\n\n# Code\n```\nclass Solution {\n public List fizzBuzz(int n) {\n LinkedList list = new LinkedList<>();\n for (int i = 1; i <= n; i++)\n {\n if (i % 15 == 0)\n list.add("FizzBuzz");\n else if (i % 3 == 0)\n list.add("Fizz");\n else if (i % 5 == 0)\n list.add("Buzz");\n else\n list.add(String.valueOf(i));\n }\n return list;\n }\n}\n```\n\n## For additional problem-solving solutions, you can explore my repository on GitHub: [GitHub Repository](https://github.com/ahmedna126/java_leetcode_challenges)\n\n\n![abcd1.jpeg](https://assets.leetcode.com/users/images/530000ff-dbd7-4cfe-a9cb-e9f1f2286cfd_1698585777.0779667.jpeg)\n23:T528,# Intuition\nThe intuition behind the above code is that we can use the modulo operator to determine if a number is divisible by another number. The modulo operator returns the remainder of a division operation. For example, 10 % 3 returns 1, because 10 divided by 3 has a remainder of 1.\n\nIn the above code, we use the modulo operator to check if the current value is divisible by 3 or 5. If the current value is divisible by 3, we add the string "Fizz" to the LinkedList. If the current value is divisible by 5, we add the string "Buzz" to the LinkedList. If the current value is divisible by

Fizz Buzz

Problem Description

Problem Description

Answer Panel