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Given strings s1 and s2, return the minimum contiguous substring part of s1, so that s2 is a subsequence of the part.
If there is no such window in s1 that covers all characters in s2, return the empty string "". If there are multiple such minimum-length windows, return the one with the left-most starting index.
Example 1:
Input: s1 = "abcdebdde", s2 = "bde" Output: "bcde" Explanation: "bcde" is the answer because it occurs before "bdde" which has the same length. "deb" is not a smaller window because the elements of s2 in the window must occur in order.
Example 2:
Input: s1 = "jmeqksfrsdcmsiwvaovztaqenprpvnbstl", s2 = "u" Output: ""
Constraints:
1 <= s1.length <= 2 * 1041 <= s2.length <= 100s1 and s2 consist of lowercase English letters.