count to 0, which will hold the final result.countSubarrays that takes a bound B and returns the number of subarrays with all elements less than or equal to B.countSubarrays, initialize cur to 0, which tracks the number of valid subarrays ending at the current position.cur when an element is less than or equal to B, and resetting cur to 0 when an element is greater than B.cur to count for each iteration, accumulating the number of valid subarrays.countSubarrays(right) - countSubarrays(left - 1).