Leetcode Problem 7. Reverse Integer

7. Reverse Integer

Leetcode Solutions

Initialize rev as 0 to store the reversed number.
Loop while the input number x is not 0: a. Perform the pop operation: pop = x % 10 and x /= 10. b. Check for overflow: if rev > INT_MAX/10 or rev < INT_MIN/10, return 0. c. If rev is at the boundary of overflow, check the last digit: if rev == INT_MAX/10 and pop > 7, or if rev == INT_MIN/10 and pop < -8, return 0. d. Perform the push operation: rev = rev * 10 + pop.
Return the reversed number rev.

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